PHS Integrated Algebra I
Sunday, January 15, 2012
Thursday, November 3, 2011
Test Correction for Unit 2.10-2.13
1) Multiplying Polynomials
(3b + 3)(b2 + 3b + 1) =
A) 3b3 + 12b2 + 6b -3
2) Multiplying polynomials
3) Adding Polynomials
4) Subtracting Polynomials
Naming Polynomials 5) - 8)
5) The problem....and the answer
6)
7)
8)
Factor quadratics with a leading coefficient of 1 (9 - 14)
9) leading coefficient of 1
10) leading coefficient of 1
11) leading coefficient of 1
12) leading coefficient of 1
13) leading coefficient of 1
14) leading coefficient of 1
Others on Algebasics, Solve by factoring on Algebasics
Page #2 Question 1-3
(3b + 3)(b2 + 3b + 1) =
A) 3b3 + 12b2 + 6b -3
2) Multiplying polynomials
3) Adding Polynomials
(6b - 7b2 + 4b3) + (5b2 + b - 2b3)
D) 2b3- 2b2 + 7b
4) Subtracting Polynomials
Naming Polynomials 5) - 8)
5) The problem....and the answer
6)
7)
8)
Factor quadratics with a leading coefficient of 1 (9 - 14)
9) leading coefficient of 1
10) leading coefficient of 1
11) leading coefficient of 1
12) leading coefficient of 1
13) leading coefficient of 1
14) leading coefficient of 1
Others on Algebasics, Solve by factoring on Algebasics
Page #2 Question 1-3
Monday, August 29, 2011
Hellen Romero c(:: average rate of change
Hellen Romero c(:: average rate of change: The change in the value of a quantity divided by the elapsed time.
Finding the zero's
Make sure you set the equation = 0 to find the zeros...don't plug in zero! That is entirely different...
If you are asked to find the zero of f(x) = 2x + 5
2x + 5 = 0...then solve for x.
x = -5/2
if you are asked f(x) = 2x + 5; f(0), then plug in zero...2(0) + 5 = 5
f(0) = 5, the zero of the function is -5/2
If you are asked to find the zero of f(x) = 2x + 5
2x + 5 = 0...then solve for x.
x = -5/2
if you are asked f(x) = 2x + 5; f(0), then plug in zero...2(0) + 5 = 5
f(0) = 5, the zero of the function is -5/2
How to Graph a linear equation
The y axis is the vertical axis....go to b (the number out there by itself), (0,b) and put a dot, then count the slope from that point...up/rt if it is positive, up/lt if it is negative
The slope is the coefficient (number in front of x) of x...just count up or down and over rt or lt...
up/rt or dn/lt is positive; up/lt or dn/rt is negative!
Friday, August 26, 2011
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