Thursday, November 3, 2011

Test Correction for Unit 2.10-2.13

1)  Multiplying Polynomials


(3b + 3)(b2 + 3b + 1) =

A) 3b3 + 12b2 + 6b -3

2)  Multiplying polynomials

3) Adding Polynomials



(6b - 7b2 + 4b3) + (5b2 + b - 2b3)

D) 2b3- 2b+ 7b


4)  Subtracting Polynomials

Naming Polynomials 5) - 8)

5) The problem....and the answer

6)

7)

8)

Factor quadratics with a leading coefficient of 1 (9 - 14)



9) leading coefficient of 1

10)  leading coefficient of 1

11)  leading coefficient of 1

12)  leading coefficient of 1

13)  leading coefficient of 1

14)  leading coefficient of 1

Others on AlgebasicsSolve by factoring on Algebasics

Page #2 Question 1-3

Monday, August 29, 2011

Hellen Romero c(:: average rate of change

Hellen Romero c(:: average rate of change: The change in the value of a quantity divided by the elapsed time.

Finding the zero's

Make sure you set the equation = 0 to find the zeros...don't plug in zero!  That is entirely different...

If you are asked to find the zero of f(x) = 2x + 5

2x + 5 = 0...then solve for x.
  x = -5/2

if you are asked f(x) = 2x + 5; f(0), then plug in zero...2(0) + 5 = 5

f(0) = 5, the zero of the function is -5/2

How to Graph a linear equation





The y axis is the vertical axis....go to b (the number out there by itself), (0,b) and put a dot, then count the slope from that point...up/rt if it is positive, up/lt if it is negative

The slope is the coefficient (number in front of x) of x...just count up or down and over rt or lt...

up/rt or dn/lt is positive; up/lt or dn/rt is negative!